Feeding a nonos pcm1704 DAC

This DAC have these modules:

1. USB interface (no PSU)
2. Shift Register (+VD0)
3. DAC = 2 x pcm1704 (+VD1, -VD1, +VD2, -VD2, +VA1, -VA1, +VA2, -VA2)
4. I/V converter: Battery charger, channels L and R: +VB1, +VB2

Total: 11 power lines.

I can imagine three different modes of powering the DAC:

1. One transformer with two secondaries, that feeds 11 voltage regulators (positive and negative.
2. Six transformers: 1 for Shift Register. Four for DAC, 1 for charge batteries.
3. An intermediate solution between 1) and 2)

I can see some obvious differences in these approaches:

With 1) only two diode bridges is good for lowering high freq. switching noise, but all GNDs are tied together.
With 2) there hare 10 diode bridges and GNDs can be independent at PSU level.
Has been stated that PCM1704 is a great performer but very sensible with PSU quality and implementation. On the other hand, BB datasheet says:

“The PCM1704 only requires a ±5V supply for operation. Both positive supplies (+VDD and +VCC) should be tied together at a single point and connected to a single +5V analog power supply. Similarly, both negative supplies (–VDD and –VCC) should be tied at a single point and connected to a single –5V analog power supply. No advantage is gained by using separate analog and digital power supplies. It is more important that the analog supplies used to drive these pins are as noise and ripple free as possible to reduce coupling of supply noise to the output.”

Obviously, all GNDs will be tied somewhere, in the PSU or elsewhere, but this will make large differences in final results.

I have attached two extreme versions of feeding.

I appreciate any suggestion.


Regards,
Luis.

Attached Files

	VERSION_00.pdf (11.8 KB)
	VERSION_01.pdf (12.0 KB)