LME49810 biasing procedure temp comp and simple resistor

I am looking to bias the lme49810 to 1.5Amps with temp compensation circuit given in the application note. The formula is as follows..
VBIAS = VCE = RB1 * I + Vbe(V)

its said that Vbe is limited to 6V in the circuit with 2sc5171 as biasing transistor.

what is the general value of vbe observed or does it changes when biasing?

what should be RB1 for a bias of 1.5amps? considering
I = 1.5A
Vbias = 10V
Vbe = 5v

so the result is RB1 being 3.3 ohms? what is the general procedure to bias in this case..